Find the sum of divisors of 544.
Method:
Find the the prime factorization of the number
Calculate the sum of its divisors
Take each different prime factor
Add together all its powers up to the one that appears in the prime factorization
And then multiply all these sums together!
Method:
Find the the prime factorization of the number
Calculate the sum of its divisors
Take each different prime factor
Add together all its powers up to the one that appears in the prime factorization
And then multiply all these sums together!
Solution:
Prime
Factorization of 544:
2 | 544
2 | 272
2 | 136
2 | 68
2 | 34
17 | 17
17 | 17
| 1
2^5 x 17^1
Exponents: 5 & 1
Sum of divisors of 544 = 1134
2^5 x 17^1
Exponents: 5 & 1
X
|
2^0
|
2^1
|
2^2
|
2^3
|
2^4
|
2^5
|
Row Sum
|
17^0
|
1
|
2
|
4
|
8
|
16
|
32
|
63
|
17^1
|
17
|
34
|
68
|
136
|
272
|
544
|
1071
|
Col Sum
|
18
|
36
|
72
|
144
|
288
|
576
|
1134
|
Sum of divisors of 544 = 1134
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