Find the sum of divisors of 544 excluding 1 and 544
Method:
Find the the prime factorization of the number
Calculate the sum of its divisors
Take each different prime factor
Add together all its powers up to the one that appears in the prime factorization
And then multiply all these sums together
Deduct the numbers to be excluded from the result
Method:
Find the the prime factorization of the number
Calculate the sum of its divisors
Take each different prime factor
Add together all its powers up to the one that appears in the prime factorization
And then multiply all these sums together
Deduct the numbers to be excluded from the result
Solution:
2 | 544
2 | 272
2 | 136
2 | 68
2 | 34
17 | 17
17 | 17
2^5
x 17^1
Exponents: 5 & 1
Sum of divisors of 544 excluding 1 and 544 = 1134 -1 - 544 = 589
Answer: 589
Exponents: 5 & 1
X
|
2^0
|
2^1
|
2^2
|
2^3
|
2^4
|
2^5
|
Row Sum
|
17^0
|
1
|
2
|
4
|
8
|
16
|
32
|
63
|
17^1
|
17
|
34
|
68
|
136
|
272
|
544
|
1071
|
Col Sum
|
18
|
36
|
72
|
144
|
288
|
576
|
1134
|
Sum of divisors of 544 excluding 1 and 544 = 1134 -1 - 544 = 589
Answer: 589
No comments:
Post a Comment