Find the number of zeroes at the end of 48!.

Find the number of zeroes at the end of 48!.

Solution:

Maximum power of 5 in 48!

= 9 + 1 

= 10

This way:

[ 48 / 5 ]  +  [48/5x5]  +  [48  / 5x5x5] + …….. [till the quotient is  greater than  zero]

= 9 + 1 + 0

= 10

Answer: 10