Find the number of zeroes at the end of 350!
Solution:
Maximum power of 5 in 350!
= 70 + 14 + 2
= 86
This way:
[ 350 / 5 ] + [350/5x5] + [350 / 5x5x5] + …….. [till the quotient is greater than zero]
= 70 + 14 + 2
= 86
Answer: 86
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