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Saturday, 23 March 2019
Find the number of zeroes at the end of 48!.
Find the number of zeroes at the end of 48!.
Solution:
Maximum power of 5 in 48!
= 9 + 1
= 10
This way:
[ 48 / 5 ] + [48/5x5] + [48 / 5x5x5] + …….. [till the quotient is greater than zero]
= 9 + 1 + 0
= 10
Answer: 10
Thursday, 14 March 2019
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